0=-4.9x^2+19x+300

Solution for 0=-4.9x^2+19x+300 equation:

0=-4.9x^2+19x+300

We move all terms to the left:

0-(-4.9x^2+19x+300)=0

We add all the numbers together, and all the variables

-(-4.9x^2+19x+300)=0

We get rid of parentheses

4.9x^2-19x-300=0

a = 4.9; b = -19; c = -300;
Δ = b2-4ac
Δ = -192-4·4.9·(-300)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-79}{2*4.9}=\frac{-60}{9.8}
=-6+1/8.1666666666667
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+79}{2*4.9}=\frac{98}{9.8}
=10
$